If h is the difference in height between the two sides of the gap, θ is the angle of the exit’s slope, V is the velocity, and g is the standard acceleration of free fall at 9.8 m/s2, the required velocity would equal to square root of 9.8m/s2 *6m2 divided by 2(h-6tanθ)*cos2θ…
We have now gotten so much conflicting feedback on this equation, that we have come to beg for a crowd consensus. Please excuse poor Illustrator skills.
A car is travelling up a slope and is about to jump a gap.
Update: everything is funnies to you, isn’t it?